# Here is a Formula for Evaluating Honors Completion Rates

Honors completion rates, as we noted in a previous post, are a complicated issue. They represent the percentage of students who enter an honors program and then complete all honors requirements for at least one completion option by the time they graduate.

They are related to university freshman retention rates and university graduation rates, but in order to evaluate them there must be some workable baseline completion rate derived from a significant sample of programs.

Honors deans and directors at 31 public university honors programs contributed the data used to calculate the values in the next paragraph, along with extensive additional data we use in rating honors programs. The 31 programs enrolled more than 64,000 honors students in Fall 2017. At some point we might include completion rates as a metric; if we do, then this formula, or an improved version, might be used.

This tentative formula takes into account (1) the average (mean) honors completion rate for the whole data set (57.88 percent); (2) the mean university-wide freshman retention rate for the whole data set (86.81 percent); (3) the completion rate of each program; (4) the freshman retention rate for the parent university of each program; and (5) the graduation rate of each university.

The formula assumes that a desirable target honors completion rate should at least equal the midway point between the university graduation rate and the adjusted honors completion rate. (See examples below, however, for programs that have honors completion rates that exceed the university graduation rate.) The formula can easily be changed to include lower or higher target levels by increasing or reducing the divisor.

H = the mean honors completion rate for the data set;

F = the mean freshman retention rate for the data set;

P = the program completion rate;

C = the completion rate of each program adjusted to the university freshman retention rate (.67*R);

R = the freshman retention rate of each parent university;

G = the graduation rate of each parent university;

T = the estimated target completion rate after the formula is applied. T = (G + C) /2. This is an estimate of what the minimum completion rate should be, given the university’s freshman retention rate and graduation rate, and the mean completion rate and mean freshman retention rate for this data set. Other data sets would of course have different data, but the formula could still be applied.

The completion rates of ten programs exceeded the graduation rates of their parent universities.

Here is the formula, where P = 61%; R = 92%; G = 83%:

First step = (H/F), or .57.88 / 86.81. The result is .67. This is a constant for this data set.

Second step is to adjust the completion rate in relation to the university freshman retention rate = .67 *R, or .67 *92. The result is 61.64 (C), a bit higher than the actual program completion rate of 61.0 (P), because of the relatively high freshman retention rate.

Third step is to adjust the completion rate C in relation to the university graduation rate in order to calculate the target completion rate. T = (G + C) /2, or (83 + 61.64) /2 = 72.32 (T).

Fourth step is to calculate P – T, which would be 61.00 – 72.32 = –11.32. This step calculates the extent to which the program completion rate varies from the estimated target rate. The program is performing below the estimated target rate. The relatively high university graduation rate is the main reason.

More examples:

Honors program A had a program completion rate (P) of 84%, a freshman retention rate (R) of 88%, and a university graduation rate (G) of 73%. The C rate would be .67*88, or 58.96. The T calculation would be (G + C) /2, or (73 + 58.96) / 2= 65.98 (T). Now calculate C – T, (or 84 – 65.98) = +18.02. This program is performing far above its estimated target rate.

Honors program B had the same program completion rate (P) of 84% but a much higher freshman retention rate (R) of 95%, and a university graduation rate (G) of 81%. Calculating the C value would be .67*95, or 63.7, and the T would (G + C) /2, or (81 – 63.7) /2 = 73.325. When we calculate C – T, (84 – 73.325), the result is + 11.675. This program is performing well above its estimated rage, but even with the same completion rate as Program A, the impact of higher graduation and freshman retention rates for Program B causes its relative performance rating to be lower than Program A. In other words, the expectations were higher for Program B. Both programs are exceptional in that their honors completion rates exceed their university graduation rates.

Honors program D had a program completion rate (P) of 40%, a freshman retention rate (R) of 82%, and a university graduation rate (G) of 53%. C would be .67*82, or 54.94. T would be (G + C) /2, or (53 + 54.94) /2 = 53.97. Calculating C – T, the result is 40 – 53.97, or -13.97. Program D is significantly underperforming based on the formula.

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